[Nickle]New function syntax

[Keith Packard]

Around 1 o'clock on Aug 7, Bart Massey wrote:

> 	poly() foo = f;
> it is unclear to me whether f is an initializer for foo or an
> expression defining it.  Note that it matters.

The = expr syntax only applies to the sugared version of function 
declarations

	poly foo () = f;

The unsugared version remains:

	poly() foo = poly func () { return f; }

> Besides, I don't want to be gratuitously incompatible with
> C, even where C is wartsy...

It's just a terse form for a very common function style, especially when
coding in a functional style.

Keith Packard        XFree86 Core Team        HP Cambridge Research Lab